How to use this tool
- Enter enthalpy change δh, entropy change δs, temperature.
- Select Calculate to view the result.
- Check the method and assumptions below before using the result.
The method, explained
ΔG = ΔH − TΔS. Divide entropy by 1,000 to match an enthalpy input in kJ/mol.
Using enthalpy change δh = -40 kJ/mol, entropy change δs = -100 J/(mol·K), temperature = 298.15 K, the result is -10.185 kJ/mol. Change these example inputs to match your task; use the method above to check each step.
Understanding your result
No. Thermodynamic favorability and reaction kinetics are different. A favorable reaction can still have a large activation barrier.
What to keep in mind
Use compatible standard or nonstandard quantities at the same conditions. Temperature dependence of ΔH and ΔS is not modeled. Educational calculation only; use validated procedures for laboratory work.
Reference: OpenStax Chemistry 2e — chemical quantities and models
Common questions
Does negative free energy mean a fast reaction?
No. Thermodynamic favorability and reaction kinetics are different. A favorable reaction can still have a large activation barrier.
Are my inputs uploaded?
No. This calculation runs in your browser without an account or an external API.
Methodology maintained by ClarityKit. How these tools are built and checked.