How to use this tool
- Enter initial equilibrium constant, reaction enthalpy, initial temperature, final temperature.
- Select Calculate to view the result.
- Check the method and assumptions below before using the result.
The method, explained
ln(K2/K1) = −ΔH/R × (1/T2 − 1/T1), with ΔH converted from kJ/mol to J/mol.
Using initial equilibrium constant = 1, reaction enthalpy = 50 kJ/mol, initial temperature = 298.15 K, final temperature = 310 K, the result is 2.1619397. Change these example inputs to match your task; use the method above to check each step.
Understanding your result
No. In this model heating increases K for an endothermic reaction (positive ΔH), and decreases K for an exothermic reaction (negative ΔH).
What to keep in mind
Assumes constant reaction enthalpy across the interval and dimensionless, consistently defined equilibrium constants. Educational calculation only; use validated procedures for laboratory work.
Reference: OpenStax Chemistry 2e — chemical quantities and models
Common questions
Does heating always increase the equilibrium constant?
No. In this model heating increases K for an endothermic reaction (positive ΔH), and decreases K for an exothermic reaction (negative ΔH).
Are my inputs uploaded?
No. This calculation runs in your browser without an account or an external API.
Methodology maintained by ClarityKit. How these tools are built and checked.