How to use this tool
- Enter thermal conductivity, area, temperature difference, thickness.
- Select Calculate to view the result.
- Check the method and assumptions below before using the result.
The method, explained
Heat-transfer rate = conductivity × area × temperature difference/thickness.
Using thermal conductivity = 0.04 W/(m·K), area = 0.5 m², temperature difference = 20 K, thickness = 0.1 m, the result is 4 W. Change these example inputs to match your task; use the method above to check each step.
What to keep in mind
One-dimensional steady state; ignores contact resistance and thermal bridges. An idealized educational model using the stated SI units. Real systems may need additional forces, losses or experimental measurements. Not a safety or equipment specification.
Common questions
Which inputs does this calculation need?
Estimate heat flow across a uniform flat slab. Enter thermal conductivity in W/(m·K), area in m², temperature difference in K, thickness in m. The filled example is editable and is not a saved personal record.
How should I interpret the result?
One-dimensional steady state; ignores contact resistance and thermal bridges. An idealized educational model using the stated SI units. Real systems may need additional forces, losses or experimental measurements. Not a safety or equipment specification.
Methodology maintained by ClarityKit. How these tools are built and checked.